Question
An 800-kg car traveling in a straight line at a speed of 30 m/s applies its brakes. During braking, there is a net force of 2000 N in the horizontal direction on the car. What distance will the car move from the time it applies its brakes until it has stopped?
Answers
a = Fn/m = 2000 / 800 =- 2.5 m/s^2.
d = (Vf^2-Vo^2)/2a,
d = (0-(30)^2 / -5 = 180 m.
d = (Vf^2-Vo^2)/2a,
d = (0-(30)^2 / -5 = 180 m.
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