Question

6. A bowl contains 10 red balls, 10 green balls and 10 white balls. a. What is the probability of drawing 2 white balls with replacement? b. What is the probability of drawing 2 white balls without replacement?

Answer 1

when balls are replaced
Prob(2white) = (10/30)(10/30) = 1/9

without replacement
prob(2white) = (10/30)(9/29) = 3/29

Answer 2

78

Answer 3

where is the fu*n solution

Answer 4

Probability of getting 2 white balls (W) with replacement is :
P(W) = ( (10/30) * (10/30) ) = 1/9

Probability of getting 2 white balls (W) without replacement is :
P(W) = ( (10/30) * (9/29) ) = 3/29