Asked by Kieron
The number of sweets in Container X was 24 more than Container Y. When I removed 42 sweets from Container X and transfered then in Container Y,the number of sweets in Container Y became thrice of Container X. Find the number of sweets in Container X first.
Answers
Answered by
Bosnian
x = The number of sweets in container x
y = The number of sweets in Container y
x = 24 + y
OR
y = x - 24
When you removed 42 sweets from container x then numers of sweets in container x became: x - 42
Numbers of sweets in container y became: y + 42 = thrice of ( x - 42 ) = 3 ( x - 42 )
y + 42 = 3 ( x - 42 )
Remark : y = x - 24
( x - 24 ) + 42 = 3 ( x - 42 )
x - 24 + 42 = 3 * x - 3 * 42
x + 18 = 3 x - 126
18 + 126 = 3 x - x
144 = 2 x
2 x = 144 Divide both sides by 2
x = 144 / 2
x = 72
y = x - 24
y = 72 - 24
y = 48
Cheking :
x - 42 = 72 - 42 = 30
y + 42 = 48 + 42 = 90
90 / 30 = 3
y = The number of sweets in Container y
x = 24 + y
OR
y = x - 24
When you removed 42 sweets from container x then numers of sweets in container x became: x - 42
Numbers of sweets in container y became: y + 42 = thrice of ( x - 42 ) = 3 ( x - 42 )
y + 42 = 3 ( x - 42 )
Remark : y = x - 24
( x - 24 ) + 42 = 3 ( x - 42 )
x - 24 + 42 = 3 * x - 3 * 42
x + 18 = 3 x - 126
18 + 126 = 3 x - x
144 = 2 x
2 x = 144 Divide both sides by 2
x = 144 / 2
x = 72
y = x - 24
y = 72 - 24
y = 48
Cheking :
x - 42 = 72 - 42 = 30
y + 42 = 48 + 42 = 90
90 / 30 = 3
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