Asked by valerie faylogna
compute for the pOH of a solution prepared by dissolving 5.50g KOH in enough to make a 100.0mL solution
Answers
Answered by
DrBob222
...........in enough WHAT? water?
moles KOH = 5.50g/molar mass KOH.
(OH^-) = moles KOH/L soln
pOH = -log(OH^-)
moles KOH = 5.50g/molar mass KOH.
(OH^-) = moles KOH/L soln
pOH = -log(OH^-)
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