Asked by Beatriz
If 38.33 mL of a standard 0.1667 M Ba(OH)2 solution is required to neutralize exactly 52 mL of H2SO4, what is the molarity of the acid solution?
Answers
Answered by
DrBob222
Ba(OH)2 + H2SO4 ==? BaSO4 + 2H2O
moles Ba(OH)2 = M x L = ?
Convert moles Ba(OH)2 to mol H2SO4.
?mol Ba(OH)2 x [1 mol H2SO4/1 mol Ba(OH)2]= ?mol Ba(OH)2 x 1/1 which means moles Ba(OH)2 = mol H2SO4.
Then M H2SO4 = moles H2SO4/L H2SO4.
moles Ba(OH)2 = M x L = ?
Convert moles Ba(OH)2 to mol H2SO4.
?mol Ba(OH)2 x [1 mol H2SO4/1 mol Ba(OH)2]= ?mol Ba(OH)2 x 1/1 which means moles Ba(OH)2 = mol H2SO4.
Then M H2SO4 = moles H2SO4/L H2SO4.
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