Asked by alex
If a metal ball is thrown downward with an initial velocity of 22 feet per second (15mph)from a 100 foot water tower, it's height h in feet above the ground after t seconds is modeled by h(t)=-16t^2-22t+100
Determine when the height of the ball is 62 feet.
Determine when the height of the ball is 62 feet.
Answers
Answered by
Damon
h = 100 - 22 t - 16 t^2
62 = 100 - 22 t - 16 t^2
16 t^2 + 22 t - 38 = 0
8 t^2 + 11 t - 19 = 0
(8 t + 19) (t - 1) = 0
t = 1 second (forget the negative time)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.