Ask a New Question

Asked by hank

find the area under the curve
y = x^2 + x from the origin to the line x = 3
13 years ago

Answers

Answered by Reiny
I will assume you want the area between the curve and the x-axis.
Under the curve would be infinitely large, it would be open below.

area = ∫ x^2 + x) dx from 0 to 3
= [(1/3)x^3 + (1/2)x^2 ] from 0 to 3
= 9 + 9/2 - 0 - 0
= 27/2 square units
13 years ago

Related Questions

Find the area under the curve y=5/x^2 between x=-3 and x=-1. Find the area above the curve starting from 0 to 1 on x-axis of y=1/(2x+1)^2 Find the area above curve y=(1/2*x-2)^6+5 enclosed by a line cutting at (0,y) and (x,y). Note.It is... Find the area above curve y=(1/2*x-2)^6+5 enclosed by a line cutting at (0,y) and (x,y). Note.It is... Find the area above curve y=(1/2*x-2)^6+5 enclosed by a line cutting at (0,y) and (x,y). Ans.438.85 Find the area above curve y=(1/2*x-2)^6+5 enclosed by a line cutting at (0,y) and (x,y). Note.It is... Find the area above curve y=(1/2*x-2)^6+5 enclosed by a line cutting at (0,y) and (x,y). Note.It is... find the area between the curve y= x^2+4x and the x - axis from x=-2 to x= 0. Find the area under the curve given by y=coax from x=0 to x=pi/4 above the x-axis. Draw a graph wit...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use