Asked by Anonymous

for a sateliite to have a speed of 7400 m/s how far must it be in metres above the earth's surface
Answered by bobpursley
V^2/(re+h)=9.8(re/(re+h))^2
solve for h.
Answered by drwls
M V^2/R = M*g*(Re/R)^2
(due to inverse square falloff in weight with R)

Re is the earth's radius = 6370*10^3 m.
R = Re^2*g/V^2 = 7.262*10^6 m = 7262 km

Distance above Earth = 7262 - 6370 km = 892 km
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