Asked by Anonymous
                for a sateliite to have a speed of 7400 m/s how far must it be in metres above the earth's surface
            
            
        Answers
                    Answered by
            bobpursley
            
    V^2/(re+h)=9.8(re/(re+h))^2 
solve for h.
    
solve for h.
                    Answered by
            drwls
            
    M V^2/R = M*g*(Re/R)^2 
(due to inverse square falloff in weight with R)
Re is the earth's radius = 6370*10^3 m.
R = Re^2*g/V^2 = 7.262*10^6 m = 7262 km
Distance above Earth = 7262 - 6370 km = 892 km
    
(due to inverse square falloff in weight with R)
Re is the earth's radius = 6370*10^3 m.
R = Re^2*g/V^2 = 7.262*10^6 m = 7262 km
Distance above Earth = 7262 - 6370 km = 892 km
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.