That can be solved by separation of variables.
y^2 dy = (x+1) dx
y^3/3 = x^2/2 + x + C
If y(0) = 3, then C = 3
y^3/3 = x^2/2 + x + 3
Consider the differential equation,
dy/dx=(x+1)/y^2
with the initial condition y(0)=3.
Write down the particular solution, and hence, calculate the value of y when x=8.7, to 3 dec places.
3 answers
3^3/3 = C
C = 9
C = 9
Steve is correct.