Question
An electron (mass m = 9.11 * 10^-31 kg) is accelerated in a uniform field vector E ( E =1.45 * 10^4 N/C) between two parallel charged plates. The seperation of the plates is 1.10 cm. The electron is accelerated from rest near the negative plate and passes through a tiny hole in the positive plate.
a) With what speed does it leave the hole?
b) Show that the gravitational force can be ignored.
a) With what speed does it leave the hole?
b) Show that the gravitational force can be ignored.
Answers
a) e E d = (1/2) mV^2
d is the plate separation
e amd m are the electron charge and mass, respiectively.
Solve for V
b) Compare Ee, (the electric force) to mg (the gravity force). The ratio may surprise you.
d is the plate separation
e amd m are the electron charge and mass, respiectively.
Solve for V
b) Compare Ee, (the electric force) to mg (the gravity force). The ratio may surprise you.
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