Question

An electron (mass m = 9.11 * 10^-31 kg) is accelerated in a uniform field vector E ( E =1.45 * 10^4 N/C) between two parallel charged plates. The seperation of the plates is 1.10 cm. The electron is accelerated from rest near the negative plate and passes through a tiny hole in the positive plate.
a) With what speed does it leave the hole?
b) Show that the gravitational force can be ignored.

Answer 1

a) e E d = (1/2) mV^2
d is the plate separation
e amd m are the electron charge and mass, respiectively.
Solve for V
b) Compare Ee, (the electric force) to mg (the gravity force). The ratio may surprise you.

Answer 2

0879798