Asked by MOHIT
The density of ice is 0.92g cm-3 & that of sea water is 1.025g cm-3.Find the total volume of an iceberg which floats with its volume 800cm3 above water?
ANSWER:7809.5cm3
ANSWER:7809.5cm3
Answers
Answered by
Henry
Va = Vi - Vb,
Va = Vi - (Di/Dw)*Vi = 800 cm^3,
Vi - (0.92/1.025)Vi = 800,
Vi - 0.898Vi = 800,
0.102Vi = 800,
Vi = 800 / 0.102 = 7843 cm^3. = Vol. of
ice.
Va = Vol. above water.
Vb = Vol. below water.
Di = Density of ice.
Dw = Density of water.
Va = Vi - (Di/Dw)*Vi = 800 cm^3,
Vi - (0.92/1.025)Vi = 800,
Vi - 0.898Vi = 800,
0.102Vi = 800,
Vi = 800 / 0.102 = 7843 cm^3. = Vol. of
ice.
Va = Vol. above water.
Vb = Vol. below water.
Di = Density of ice.
Dw = Density of water.
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