Asked by Scooby10
If f(x) = (square root of (3x^2 - 5x + 7)), then f'(2) =
Answers
Answered by
jack
f'(x) = 6x - 5 / 2 sqrt(3x^2-5x+7)
f'(2) = 12 - 5 / 2 sqrt ( 12-10+7)
= 7 / 2 sqrt (9)
= 7/ 2*3
= 7/6
= 1.16666
f'(2) = 12 - 5 / 2 sqrt ( 12-10+7)
= 7 / 2 sqrt (9)
= 7/ 2*3
= 7/6
= 1.16666
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