Asked by Carey

A researcher studying the nutritional value of a new candy places a 4.90 gram sample of the candy inside a bomb calorimeter and combusts it in excess oxygen. The observed temperature increase is 2.75 Celsius. If the heat capacity of the calorimeter is 29.50 kJ K^-1, how many nutritional calories are there per gram of the candy? Answer in cal/g

Answers

Answered by DrBob222
29,500 J/K x 2.75 K = about 81,000 J(approximate) from the combustion.
81,000 J/4.90 = about 16,000 J/g.
16,000 J/g x (1 cal/4.184 J) = about 4,000 cal.
4,000 cal = 4 kcal = about 4 nutritional calories.
Answered by Carey
that's amazing... thank you so much Dr Bob!
Answered by Angela
Thank you so much!!! That helped me too!
Answered by Anonymous
Grub!
Answered by Anonymous
Wouldn't you have to convert the temperature to K in order to cancel out the units and obtain a value in joules. For the very first step of the solution
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