Mary has read 1/3 of a 240-page book. How many pages does she still have to read to finish the book? What percent of the book does she still have to read?

User Icon for Anonymous Anonymous answered
12 years ago

240 * ( 1 / 3 ) = 240 / 3 = 80

240 - 80 = 160

OR

1 - 1 / 3 = 3 / 3 - 1 / 3 = 2 / 3

240 * 2 / 3 = 480 / 3 = 160

User Icon for jake jake answered
2 years ago

thanks

anonymous anonymous answered
1 year ago

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User Icon for Clown Bot Clown Bot answered
1 year ago

Well, Mary has read 1/3 of a 240-page book, which means she has read (1/3) * 240 = 80 pages. So, how many pages does she still have to read? Well, if she has read 80 pages, and the book has 240 pages, then she still has 240 - 80 = 160 pages to read.

As for the percentage of the book she still has to read, let's calculate that. If she has 160 pages left to read and the entire book has 240 pages, we can calculate the percentage by dividing 160 by 240 and multiplying the result by 100. Wait, let me get my calculator... *beep boop beep* Alright, the result is 66.66666666666... percent. But let's round it up to 66.67 percent, just because I like to be precise like that. So, Mary still has to read approximately 66.67% of the book.

I hope that helps, and remember, when in doubt, just keep clowning around! 🤡

User Icon for Explain Bot Explain Bot answered
11 months ago

To find out how many pages Mary still has to read to finish the book, we first need to calculate the number of pages she has already read. We can do this by finding 1/3 of the total number of pages.

1/3 * 240 = 80 pages.

Since Mary has already read 80 pages, the number of pages she still has to read can be found by subtracting this amount from the total number of pages.

240 - 80 = 160 pages.

Therefore, Mary still has to read 160 pages to finish the book.

To calculate the percentage of the book that Mary still has to read, we can divide the number of pages she still has to read by the total number of pages and then multiply by 100.

(160 / 240) * 100 = 66.67%.

So, Mary still has to read approximately 66.67% of the book.