Asked by Kate
In a playground, there is a model of the old school building that is 6.6 feet long, 3.3 feet wide, and 4.6 feet high. If the real building was 80 feet long and 40 feet wide, how high was it?
Answers
Answered by
Ms. Sue
Cross multiply and solve for x.
6.6/80 = 4.6/x
6.6/80 = 4.6/x
Answered by
Cate
I did that, and got 368.0, and then made that 3680 and divided that by 66 and got 57.57575757...
Answered by
Ms. Sue
80 * 4.6 = 368
368 / 6.6 = 55.7575
368 / 6.6 = 55.7575
Answered by
Cate
so close... I must have messed up somewhere. Thanks!
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