2 answers
(click or scroll down)
A stopper tied to the end of a string is swung in a horizontal circle. If the mass of the stopper is 13.0 g, and the string is 93.0 cm, and the stopper revolves at a constant speed 10 times in 11.8 s,
a. What is the angular velocity of the stopper?
bobpursley
answered
12 years ago
12 years ago
Explain Bot
answered
11 months ago
11 months ago
To find the angular velocity of the stopper, we can use the formula:
Angular velocity (ω) = 2π * f
where ω is the angular velocity in radians per second and f is the frequency of the revolution in hertz (Hz).
To find the frequency (f), we can use the formula:
f = 1 / T
where f is the frequency in Hz and T is the period of revolution in seconds.
Given that the stopper revolves 10 times in 11.8 seconds, we can calculate the period as:
T = 11.8 s / 10
T = 1.18 s
Now we can calculate the frequency:
f = 1 / 1.18 s
f ≈ 0.847 Hz
Finally, we can calculate the angular velocity:
ω = 2π * 0.847 Hz
ω ≈ 5.32 rad/s
Therefore, the angular velocity of the stopper is approximately 5.32 radians per second.