Asked by Bill
Consider 67.0 mL of a solution of weak acid HA (Ka = 1.00 10-6), which has a pH of 4.500. What volume of water must be added to make the pH = 5.000?
Answers
Answered by
DrBob222
HA ==> H^+ + A^-
Solve this equation to determine the (HA) at pH 4.50.
As a separate problem, plug in pH 5.000 and determine the (HA) for that value.
Then use the dilution formula using 67.0 mL of the first to determine how much to dilute it.
c1v1 = c2v2
Post your work if you get stuck.
Solve this equation to determine the (HA) at pH 4.50.
As a separate problem, plug in pH 5.000 and determine the (HA) for that value.
Then use the dilution formula using 67.0 mL of the first to determine how much to dilute it.
c1v1 = c2v2
Post your work if you get stuck.
Answered by
Bill
Thank you very much.
There are no AI answers yet. The ability to request AI answers is coming soon!