Asked by Theresa
I need help solving Integral from 0 to (a/sqrt(b)) of (a^2-bx^2)^(3/2) I got (a^4/8sqrt(b)) - 3a^4pi/4sqrt(b)
Answers
Answered by
Writeacher
Assistance needed.
SDSU = ??
SDSU = ??
Answered by
Reiny
∫(a^2 - bx^2) dx
As a test, I let a=2 and b=3 and ran it through
the Wolfram integrator.
Looks at the mess I got with nice numbers....
I have idea.
Do you have a table of integrals?
See if you can find your pattern.
http://integrals.wolfram.com/index.jsp?expr=%284-3x%5E2%29%5E%283%2F2%29&random=false
As a test, I let a=2 and b=3 and ran it through
the Wolfram integrator.
Looks at the mess I got with nice numbers....
I have idea.
Do you have a table of integrals?
See if you can find your pattern.
http://integrals.wolfram.com/index.jsp?expr=%284-3x%5E2%29%5E%283%2F2%29&random=false
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