Asked by arvin
the lengths of the triangle are consecutive odd integers, find the length of the shortest side if the perimeter is 19 units shorter than 4 times the lenghts of that side
Answers
Answered by
Steve
let the sides be n-2,n,n+2
p = 3n = 4(n-2) - 19
3n = 4n - 8 - 19
-n = -27
n = 27
so, the sides are 25,27,29
81 = 4*25 - 19
p = 3n = 4(n-2) - 19
3n = 4n - 8 - 19
-n = -27
n = 27
so, the sides are 25,27,29
81 = 4*25 - 19