good question.
|x| = x if x>=0
So, your answer of 11 correctly solves
3x > 33
But, |x| = -x if x < 0
so, the other condition is
-3x > 33
x < -11
So, if x is farther than 11 units from 0, in either direction, 3x is farther than 33 units away from 0.
please check answers and change if wrong thank you.
The absolute value of 3 times a number x is greater than 33.
|3x| > 33
3x > 33
x > 11
what about -11
2 answers
thank you very much for your help, anonymous. thanks ann