Asked by Fustrated
The base of a regular pyramid is a square whose sides have a length 8 cm. If a lateral edge of this pyramid has length 20 cm, what is the surface area of the pyramid?
Answers
Answered by
Reiny
Look at one of the triangles, which is isosceles with a base of 8 and each of the equal sides of length 20
Height of triangle: let it be h
h^2 + 4^2 = 20^2
h^2 = 384
h = √384
Area of one triangle = (1/2)(8)(√384) = 4√384
Assuming the surface area consists only of the 4 triangles,
surface area = 4(4√384) or 16(8√6) = 128√6
Height of triangle: let it be h
h^2 + 4^2 = 20^2
h^2 = 384
h = √384
Area of one triangle = (1/2)(8)(√384) = 4√384
Assuming the surface area consists only of the 4 triangles,
surface area = 4(4√384) or 16(8√6) = 128√6
Answered by
Fustrated
Thanks, but I need the base too - that I can do by myself!
Answered by
Feleg
One edge of a right square pyramid is 6cm long. If the length of the lateral edge is 8cm, then find: its total surface area
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