Asked by Jeremy
A dilute aqueous solution of an organic compound soluble in water is formed by dissolving 2.35 g of the compound in water to form 0.250 L solution. The resulting solution has an osmotic pressure of 0.605 atm at 25 Celsius.
Assuming that the organic compound is a nonelectrolyte, what is its molar mass?
Please explain in depth all steps. I am very confused.
Assuming that the organic compound is a nonelectrolyte, what is its molar mass?
Please explain in depth all steps. I am very confused.
Answers
Answered by
DrBob222
pi = MRT
You know pi, R, T. Solve for M = moles/L
You now know M and L, solve for moles.
Then moles = grams/molar mass. You know moles and grams, solve fo molar mass.
You know pi, R, T. Solve for M = moles/L
You now know M and L, solve for moles.
Then moles = grams/molar mass. You know moles and grams, solve fo molar mass.
Answered by
Timothy Tornes
GIve me the solution
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