Question

Write an equation of the line containing the given point and parallel to the given line. (6,-7):9x-8y=3 The equation of the line is y=

Answer 1

Solve for the slope of the 9x-8y=3. You get y= 9/8x - 3/8. So your slope is 9/8. Because the line is parallel. You then use point slope formula to get equation of line in y=mx+b form.(slope form).
So y-y1=m(x-x1)
y-(-7)=9/8(x-6)
y+7=9/8(x-6)
So y=9/8x -55/4

I did the math in my head so double check the arithmetic.

Answer 2

First, get the slope of the equation by writing it in the form y=mx+b.
given: 9x-8y=3
(-8y=-9x+3)/-8
y=8/9x-3/8
slope=8/9

use point-slope form
m=8/9 and (6,-7)
y-(-7)=8/9(x-6)
y+7=8/9x-48/9
y=8/9x-48/9-7

Final answer: y=8/9x - 37/3

Answer 3

sorry i got a wrong slope... this is the correct answer...

9x-8y=3
(-8y=-9x+3)/-8
y=9/8x - 3/8
m=9/8

given: m= 9/8 and (6,-7)
y-(-7)=9/8(x-6)
y+7=9/8x-27/4
y=9/8x-27/4-7

y=9/8x-55/4 final answer...

Answer 4

9x-8y=-2