Asked by Anonymous
An internet supplier of refilled ink cartridges for ink jet printers sold cartridges to 30,000 customers over the past two months. A random sample of 1000 of those customers revealed that 18% were not happy with their purchase. The margin of error was 2%. What range is likely to contain the population parameter?
29,000 to 31,000
14% to 22%
16% to 20%
480 to 600
29,000 to 31,000
14% to 22%
16% to 20%
480 to 600
Answers
Answered by
MathGuru
.18 + or - .02 = range likely to contain population parameter
.18 + .02 = .20
.18 - .02 = .16
16% to 20% -->converting decimals to percents
.18 + .02 = .20
.18 - .02 = .16
16% to 20% -->converting decimals to percents
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