Asked by Bash
Just as a car starts to accelerate from rest with an acceleration of 1.4m/s2,a bus moving with a constant speed of 12m/s passes it in a parallel line.
1.How long the car overtakes the bus.
2.How fast will the car then be going.
3.How far will the car then have gone.
1.How long the car overtakes the bus.
2.How fast will the car then be going.
3.How far will the car then have gone.
Answers
Answered by
drwls
1. Xcar = 0.7 t^2
Xbus = 12 t
0.7t^2 = 12t
0.7 t = 12
t = 17.14 seconds
Set Xbus = Xcar and solve for t
2. Use the t from part 1 and
Vcar = 1.4 t
to get the car's velocity.
3. Use the t from part 1 and either of the X equations, to get the distance travelled.
Xbus = 12 t
0.7t^2 = 12t
0.7 t = 12
t = 17.14 seconds
Set Xbus = Xcar and solve for t
2. Use the t from part 1 and
Vcar = 1.4 t
to get the car's velocity.
3. Use the t from part 1 and either of the X equations, to get the distance travelled.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.