Asked by Matt
SImplify:
(x - 9/x) / (1 + x/3)
and (m^-1 + n^-1) / (m^-3 + n^-3)
I have no idea what to do
(x - 9/x) / (1 + x/3)
and (m^-1 + n^-1) / (m^-3 + n^-3)
I have no idea what to do
Answers
Answered by
Miley
Answer to #2:
m^4n^2.
I subtracted the m's and subtracted the m's. It's one of the exponent rules.
I have NO idea how to do the first question.
m^4n^2.
I subtracted the m's and subtracted the m's. It's one of the exponent rules.
I have NO idea how to do the first question.
Answered by
Matt
you cant do that, Miley, the m's and n's are separated by an addition sign, so you cant use the quotient of powers rule
Answered by
Miley
oh okay sry, at least i tried
Answered by
Reiny
for the first one, just multiply them using FOIL
to get
x + (x^2)/3 - 9/x - 3
for the second, use the rule for negative exponents to write
(1/m + 1/n)/(1/m^3 + 1/n^3)
finding common denominators and simplifying both top and bottom I got
(m+n)/mn / (m^3 + n^3)/m^3n^3
= (m+n)/mn * (m^3n^3)/(m^3 + n^3)
= m^2n^2(m+n) / (m^3 + n^3)
the bottom factors to (m+n)(m^2 - mn + n^2)
so we have
m^2n^2(m+n) / ((m+n)(m^2 - mn + n^2))
= m^2n^2 / (m^2 - mn + n^2)
to get
x + (x^2)/3 - 9/x - 3
for the second, use the rule for negative exponents to write
(1/m + 1/n)/(1/m^3 + 1/n^3)
finding common denominators and simplifying both top and bottom I got
(m+n)/mn / (m^3 + n^3)/m^3n^3
= (m+n)/mn * (m^3n^3)/(m^3 + n^3)
= m^2n^2(m+n) / (m^3 + n^3)
the bottom factors to (m+n)(m^2 - mn + n^2)
so we have
m^2n^2(m+n) / ((m+n)(m^2 - mn + n^2))
= m^2n^2 / (m^2 - mn + n^2)
There are no AI answers yet. The ability to request AI answers is coming soon!