Asked by Anna King
If exactly 100.0 grams of NaCl (molecular mass = 58.44 g/mol) are dissolved in 300 grams of water (molecular mass = 18.02 g/mol), the mole fraction of NaCl is
a) 1.71
b) 0.0932
c) 0.250
d) 0.103
e) 4.75
a) 1.71
b) 0.0932
c) 0.250
d) 0.103
e) 4.75
Answers
Answered by
DrBob222
moles NaCl = grams/molar mass.
moles H2O = grams/molar mass
total moles = nH2O + nNaCl
XNaCl = n NaCl/total moles.
moles H2O = grams/molar mass
total moles = nH2O + nNaCl
XNaCl = n NaCl/total moles.
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