Asked by ELIJAH B
What is the empirical of compound (X) going through the following decomposition reaction?
X = sulfur + oxygen + nitrogen
sulfur = 21 gr
oxygen = 69.70gr
nitrogen = 6.10gr
X = sulfur + oxygen + nitrogen
sulfur = 21 gr
oxygen = 69.70gr
nitrogen = 6.10gr
Answers
Answered by
DrBob222
Convert g to moles. moles = grams/molar mass.
Then find the ratio of the elements to each other with the smallest number being 1.00. The easy way to do that is to divide the smallest number by itself followed by dividing all of the other numbers by the same small number. Then round to whole numbers EXCEPT don't round more than 0.1 or so. What I mean by that is that if you come up with 1.5 obviously that number could be multiplied by a whole number (2) to obtain 3.
All of the other numbers would be multiplied by 2 also. Post your workif you get stuck.
Then find the ratio of the elements to each other with the smallest number being 1.00. The easy way to do that is to divide the smallest number by itself followed by dividing all of the other numbers by the same small number. Then round to whole numbers EXCEPT don't round more than 0.1 or so. What I mean by that is that if you come up with 1.5 obviously that number could be multiplied by a whole number (2) to obtain 3.
All of the other numbers would be multiplied by 2 also. Post your workif you get stuck.
Answered by
ELIJAH B
Would the answer to the X = S2O10N
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