Question

A bicycle and its rider together have a mass of 80 kg. If the bicycle's speed is 6m/s, how much force is needed to bring it to a stop in 4 seconds

Answer 1

a= F/masstotal

vf=Vi+at
0=6+F/80 * 4

solve for F.

Answer 2

a=change in vel./time

6m/s-0m/s divided by 4 sec.

acc. = 1.5 m/s^2

F=ma
F= (80 kg)(1.5m/s^2)
F=120N

Hope this helps! :D

Answer 3

a force of 20n gives a brick an acceleration of 5m/s^2. what force would be needed to give the brick an acceleration of 1m/s^2