Asked by Catherine
Two charges of equal magnitude of 2C and mass of 1.0 g are separated by a distance of 3 mm. Find the velocity of one particle when they are separated by a distance of 4mm.
Answers
Answered by
drwls
Are both particles free to move? Was the velocity 0 when they were 3 mm apart?
If so, they move at equal velocity in opposite directions. Use conservation of energy and the change in electrostatic potential energy to compute the increase in kinetic energy.
kQ^2/0.003m - kQ^2/0.004m = 2*(1/2) M V^2
M = 0.001 kg
k is the Coulomb constant
If so, they move at equal velocity in opposite directions. Use conservation of energy and the change in electrostatic potential energy to compute the increase in kinetic energy.
kQ^2/0.003m - kQ^2/0.004m = 2*(1/2) M V^2
M = 0.001 kg
k is the Coulomb constant
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