Asked by ceasar
A bomb is dropped from a height of 40m.simultaneously and vertically below it,a second bomb is fired vertically with a velocity of 20m/s.At what distance from the ground do they collide
Answers
Answered by
drwls
(1) Write equations for the height of each bomb vs t,
(2) Set then equal and solve for t.
(3) Use that t and either height equation to solve for location
Y1 = 40 -4.9 t^2
Y2 = 20t - 4.9 t^2
Y1 = Y2 when t = 2 seconds
Solve for either Y.
(2) Set then equal and solve for t.
(3) Use that t and either height equation to solve for location
Y1 = 40 -4.9 t^2
Y2 = 20t - 4.9 t^2
Y1 = Y2 when t = 2 seconds
Solve for either Y.
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