Asked by Brody
If there were no air resistance, a quarter dropped from the top of New York's empire state building would reach the ground 9.6 seconds later, what would its speed be? How high is the building?
Answers
Answered by
DrBob222
distance = 1/2*g*t^2
velocity = g*t
velocity = g*t
Answered by
Brody
I don't know how to use those formulas to figure out what the speed and how high the building would be ?
Answered by
DrBob222
distance = 1/2*g*t^2
distance is what you want.
1/2 is obvious.
g = 9.8 meters/secnd/second
t = time = 9.6 seconds in the problem. Solve for d.
distance is what you want.
1/2 is obvious.
g = 9.8 meters/secnd/second
t = time = 9.6 seconds in the problem. Solve for d.
Answered by
Brody
Okay, thank you! I'm pretty sure I got it! What about to know how high the building is though? Sorry if you already answered that too, I am awful with this kind of stuff
Answered by
DrBob222
The distance IS how high.
There are no AI answers yet. The ability to request AI answers is coming soon!