Asked by Robb
An object has a weight of 0.852 N. It is suspended from a scale, which reads 0.749 N when the piece is submerged in water. What is the volume of the piece of metal?
Answers
Answered by
drwls
Buoyancy force = 0.103 N
0.103 N = V*(water density)*g
0.852 N = V*(object density)*g
(Object density)/(water density) = 8.27
Object density = 8.27*10^3 kg/m^3
Object volume = V = 0.852/[9.81*8.27*10^3)]
= 1.05*10^5 m^3 = 10.5 cm^3
0.103 N = V*(water density)*g
0.852 N = V*(object density)*g
(Object density)/(water density) = 8.27
Object density = 8.27*10^3 kg/m^3
Object volume = V = 0.852/[9.81*8.27*10^3)]
= 1.05*10^5 m^3 = 10.5 cm^3
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.