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Asked by Anonymous

Find the constant acceleration of a particle whose velocity changes by 3.06 m/s every 0.093 s.
13 years ago

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Answered by Damon
a = dv/dt = (3.06 / 0.093) m/s^2
13 years ago
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Find the constant acceleration of a particle whose velocity changes by 3.06 m/s every 0.093 s.

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