Asked by Nita
An aqueous solution of calcium chloride boils at 101.3. How many kilograms of calcium chloride were dissolved in 1000 g of the solvent?
Answers
Answered by
bobpursley
CaCl2 is three particles per molecule.
deltaTemp=1.3=.52*molality
solve for molality, then
molality= moles/1000 solve for moles, then finally,grams of CaCl2 from moles, then divide by 1000 to get kg
deltaTemp=1.3=.52*molality
solve for molality, then
molality= moles/1000 solve for moles, then finally,grams of CaCl2 from moles, then divide by 1000 to get kg
Answer
0.0936
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