Use the disk or the shell method to find the volume of the solid generated by revolving the region bounded by the graphs of the equations about each given line.

y = x3
y = 0
x = 3

the x-axis,the y-axis,and the line x = 4

1 answer

I will assume your curve is y = x^3

first part:
Volume = π∫y^2 dx from 0 to 3
= π∫x^6 dx from 0 to 3
= π[(1/7)x^7] from 0 to 3
= π(2187/7 - 0) = 2187π/7

2nd part
(you will need x = .... from y = x^3
x^3 = y
x = y^(1/3)

vol = π∫(3 - y^(1/3) )^2 dy from y = 0 to y = 27
expand, then integrate etc.