Asked by Ana
If you react 2.0 g AgNO3 and 2.5 g Na2SO4, what is the percent yield if the actual yield is 1.6 g Ag2SO4? 2AgNO3 + Na2SO4 → Ag2SO4 + 2NaNO3
Answers
Answered by
DrBob222
Do you know the limiting reagent?
1. Convert g AgNO3 to moles. moles = grams/molar mass.
2. Convert g Na2SO4 to moles.
3a. Using the coefficients in the balanced equation, convert moles AgNO3 to moles Ag2SO4.
3b. Same process convert moles Na2SO4 to moles Ag2SO4.
3c. Both answers can't be correct; the correct one in limiting reagent problems is ALWAYS the smaller value and the reagent producing that value is the limiting reagent.
4. The smaller value moles x molar mass = grams Ag2SO4. This is the theoretical yield which we can call TE.
5. %yield = (actual yield/TE)*100 = ?
1. Convert g AgNO3 to moles. moles = grams/molar mass.
2. Convert g Na2SO4 to moles.
3a. Using the coefficients in the balanced equation, convert moles AgNO3 to moles Ag2SO4.
3b. Same process convert moles Na2SO4 to moles Ag2SO4.
3c. Both answers can't be correct; the correct one in limiting reagent problems is ALWAYS the smaller value and the reagent producing that value is the limiting reagent.
4. The smaller value moles x molar mass = grams Ag2SO4. This is the theoretical yield which we can call TE.
5. %yield = (actual yield/TE)*100 = ?
Answered by
janice
12312
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