Asked by jules
If f(x) = xe^-x then at x=0 is f increasing, decreasing, relative max, relative min or that f' doesn't exist?
I'm not sure, but I think it's decreasing, relative max or doesn't exist but I really have no idea. Thanks for your help!
I'm not sure, but I think it's decreasing, relative max or doesn't exist but I really have no idea. Thanks for your help!
Answers
Answered by
Steve
f = xe^-x
f' = (1-x)e^-x
at x=0, f' > 0 so f is increasing
remember that e^0 = 1
f' = (1-x)e^-x
at x=0, f' > 0 so f is increasing
remember that e^0 = 1
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