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If f(x) = xe^-x then at x=0 is f increasing, decreasing, relative max, relative min or that f' doesn't exist?

I'm not sure, but I think it's decreasing, relative max or doesn't exist but I really have no idea. Thanks for your help!

1 answer

f = xe^-x
f' = (1-x)e^-x

at x=0, f' > 0 so f is increasing

remember that e^0 = 1

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