v = Int(πr^2 dx)[0,π]
r = y = 15sinx
v = 225π*Int(sin^2 x dx)[0,π]
= 225π * π/2 = 225π2/2
Use the disk method to find the volume of the solid generated when the region bounded by y=15sinx and y=0, for 0 </= x </= pi, is revolved about the x-axis.
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