Asked by Priya
the points M(6,-8) and E(8,6) are on a circle with radius 10 units. Determine the equation of the line equidistant from points M and E
Answers
Answered by
Steve
what does the circle have to do with it?
The midpoint of ME is (7,-1)
The slope of ME is 14/2 = 7
The slope of the perpendicular bisector of ME is thus -1/7
The line is thus
(y+1)/(x-7) = -1/7
y = -x/7
Makes sense, since the circle is x^2 + y^2 = 100, and the perpendicular bisector of ME must pass through the center of the circle, or (0,0).
The midpoint of ME is (7,-1)
The slope of ME is 14/2 = 7
The slope of the perpendicular bisector of ME is thus -1/7
The line is thus
(y+1)/(x-7) = -1/7
y = -x/7
Makes sense, since the circle is x^2 + y^2 = 100, and the perpendicular bisector of ME must pass through the center of the circle, or (0,0).
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