Asked by joan
A uniform steel chain 20 m long and with a mass of 5 kg per m, hangs vertically. Compute the work required to wind it up
Answers
Answered by
drwls
The center of mass must be raised 10 m. The work required to do that is
(10 m)*(mass)*g = 10m*100kg*9.8 m/s^2 = 9800 Joules
(10 m)*(mass)*g = 10m*100kg*9.8 m/s^2 = 9800 Joules
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.