Asked by Cooper
The electric flux through each of the six sides of a rectangular box are as follows:
phi 1= +150.0 N*m^2/C; phi 2= +250.0 N*m^2/C;
phi 3= -350.0 N*m^2/C; phi 4= +175.0 N*m^2/C;
phi 5= -100.0 N*m^2/C; phi 6= +450.0 N*m^2/C
How much charge is in this box?
phi 1= +150.0 N*m^2/C; phi 2= +250.0 N*m^2/C;
phi 3= -350.0 N*m^2/C; phi 4= +175.0 N*m^2/C;
phi 5= -100.0 N*m^2/C; phi 6= +450.0 N*m^2/C
How much charge is in this box?
Answers
Answered by
drwls
Add them up and apply Gauss' law to the sum.
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