The problem can be restated as follows: 30 kJ heat released when 4.00 g Al reacts; how much heat released when 1 mol (26.98 g) Al reacts. That will be
30 x (26.98/4.00) = ?
For the reaction Al (s) + 3 HCl (aq) à AlCl3 (s) + ₃/₂ H2 (g), it was observed
that when 4.00 g of aluminum reacted with excess HCl, exactly 30.0 kJ of heat
were released. The DHo for this reaction is
a) – 91.3 kJ
b) – 120 kJ
c) – 202 kJ
d) – 7.50 kJ
no idea please leave helpful steps thanks
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