Asked by Dhehta
use a formula sheet (i never got it) to help answer this:
sin(75degrees)
sin(75degrees)
Answers
Answered by
bobpursley
I suspect you need the sine of the sum of two angles, 45+30
Sin(A+B)=SinAcosB+cosAsinB
http://www.sosmath.com/trig/Trig5/trig5/trig5.html
I suspect you are suffering from lack of routine use of flash cards. Millions of students before you have suffered through memorizing these, as I did 55 years ago. Surely you can bear the pain.
Sin(A+B)=SinAcosB+cosAsinB
http://www.sosmath.com/trig/Trig5/trig5/trig5.html
I suspect you are suffering from lack of routine use of flash cards. Millions of students before you have suffered through memorizing these, as I did 55 years ago. Surely you can bear the pain.
Answered by
Damon
I will make a guess at what is intended:
75 = 90 - 15
sin (a-b) = sin a cos b - cos a sin b
so
sin 90 cos 15 - cos 90 sin 15
= 1 cos 15 - 0 sin 15
= cos 15
15 = 30/2
cos a/2 = sqrt [(1+cos a)/2]
so
sqrt [ (1 + cos 30)/2 ]
but cos 30 = sqrt 3/2
so
sqrt [ (2+sqrt 3)/4 ]
75 = 90 - 15
sin (a-b) = sin a cos b - cos a sin b
so
sin 90 cos 15 - cos 90 sin 15
= 1 cos 15 - 0 sin 15
= cos 15
15 = 30/2
cos a/2 = sqrt [(1+cos a)/2]
so
sqrt [ (1 + cos 30)/2 ]
but cos 30 = sqrt 3/2
so
sqrt [ (2+sqrt 3)/4 ]
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