The temperature of the water will drop as heat is added to the thermometer as it reaches an equilibrium temperature.
The specific heat of the water is 4.18 kJ/Kg*K
heat gained by thermometer
= heat lost by water
0.055*(0.837)(44 - 15) = 0.300*(4.18)(T - 44)
1.335 = 1.254 (T-44)
T - 44 = 1.08
T = 45.08 C is the initial water temperature
A thermometer of mass 0.0550 kg and of specific heat 0.837 kJ/kg•K reads 15.0°C. It is then completely immersed in 0.300 kg of water, and it comes to the same final temperature as the water. If the thermometer reads 44.0 °C, what was the temperature of the water before the insertion of the thermometer?
1 answer
1 answer