Asked by Jane

Please show me how to solve:

Doctors can use radioactive iodine to treat some forms of cancer. The half-life of iodine - 131 is 8 days. A patient receives a treatment of 12 millicuries of iodine - 131. (A mullicurie is a unit of radioactivity.) How much iodine - 131 remains in the patient 16 days later?

Answers

Answered by Reiny
amount = 12 (1/2)^(168)
= 12(1/2)^2 = 3 millicuries
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions