Asked by Abby
You are at a baseball game and the pticher throws a fast ball that accelerates to the batter at 50 m/s^2. Assume that the baseball has a mass of 0.15 kg. How much force (in Newtons) must the batter apply to the ball to lay down a perfect bunt that stops dead in front of home plate?
Answers
Answered by
drwls
Baseballs do not accelerate after being released. You (or your instructor) seem to be confusing acceleration with velocity.
A reasonable speed for a fast ball is 95 mph = 42.5 m/s
Even Sandy Koufax could not throw at 50 m/s, but he came close.
If they had wanted you to compute the force necessary to bunt the ball to a stop, when thrown at that SPEED, they should have told you the time interval of ball-bat contact, or how far the bat is retracted during the bunt.
IF 50 m/s^2 is the deceleration rate that the bat must apply to the ball, then use F = m*a for the force that the bat applies.
I wonder what school district or online institution would assign such a misguided question.
A reasonable speed for a fast ball is 95 mph = 42.5 m/s
Even Sandy Koufax could not throw at 50 m/s, but he came close.
If they had wanted you to compute the force necessary to bunt the ball to a stop, when thrown at that SPEED, they should have told you the time interval of ball-bat contact, or how far the bat is retracted during the bunt.
IF 50 m/s^2 is the deceleration rate that the bat must apply to the ball, then use F = m*a for the force that the bat applies.
I wonder what school district or online institution would assign such a misguided question.
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