Asked by Abdela said yimer
                In an arthmetic sequence, the fourth term is 84 and the tenth term is 60. Find the maximum possible partial sum.
            
            
        Answers
                    Answered by
            Steve
            
    a+3d = 84
a+9d = 60
-6d = 24
d = -4
a = 96
Since the terms decrease, the maximum partial sum is just the first term: 96
    
a+9d = 60
-6d = 24
d = -4
a = 96
Since the terms decrease, the maximum partial sum is just the first term: 96
                    Answered by
            Eyob Haile
            
    96
    
                    Answered by
            Klaaer
            
    I am not clear with that
    
                    Answered by
            Muhammed
            
    1200
    
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