Question
Find the average value over the given interval.
y=3x^5; [-3,3]
I can't seem to get the answer, 0.
1/(3+3) [integral -3 to 3 (3x^5)dx]
and I get 273/2
y=3x^5; [-3,3]
I can't seem to get the answer, 0.
1/(3+3) [integral -3 to 3 (3x^5)dx]
and I get 273/2
Answers
Anonymous
I took the antiderivative incorrectly. I figured out my mistake.