Asked by Rob
find the LCM of y^2+6y+9 and y^2+y-6
Answers
Answered by
h8er_for_h8er
y^3+6y^2+9y=Y*(Y^2+6Y+9)=Y*(Y+3)^2
y^2-6y=Y*(Y-6)
The unique factors are therefore Y, (Y+3)^2 & (Y-6)
Y*(Y+3)^2*(Y-6) is the lcm
y^2-6y=Y*(Y-6)
The unique factors are therefore Y, (Y+3)^2 & (Y-6)
Y*(Y+3)^2*(Y-6) is the lcm
Answered by
Reiny
y^2 + 6y + 9
= (y+3)^2
y^2 + y - 6
= (y+3)(y-2)
so LCM = (y-2)(y+3)^2
= (y+3)^2
y^2 + y - 6
= (y+3)(y-2)
so LCM = (y-2)(y+3)^2
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